Solve (1-04^4*315/25:9/55-6:17/13))

$$( 1 - 04 ^ { 4 } \cdot 3 \frac { 15 } { 25 } : \frac { 9 } { 55 } - 6 : 1 \frac { 7 } { 13 } ) )$$

Evaluate

$$-\frac{29}{10}=-2.9$$

Solution Steps

Calculate 4 to the power of 4 and get 256.

$$1-\frac{0\times 256\times \frac{3\times 25+15}{25}}{\frac{9}{55}}-\frac{6}{\frac{1\times 13+7}{13}}$$

Multiply 0 and 256 to get 0.

$$1-\frac{0\times \frac{3\times 25+15}{25}}{\frac{9}{55}}-\frac{6}{\frac{1\times 13+7}{13}}$$

Multiply 3 and 25 to get 75.

$$1-\frac{0\times \frac{75+15}{25}}{\frac{9}{55}}-\frac{6}{\frac{1\times 13+7}{13}}$$

Add 75 and 15 to get 90.

$$1-\frac{0\times \frac{90}{25}}{\frac{9}{55}}-\frac{6}{\frac{1\times 13+7}{13}}$$

Reduce the fraction \frac{90}{25} to lowest terms by extracting and canceling out 5.

$$1-\frac{0\times \frac{18}{5}}{\frac{9}{55}}-\frac{6}{\frac{1\times 13+7}{13}}$$

Multiply 0 and \frac{18}{5} to get 0.

$$1-\frac{0}{\frac{9}{55}}-\frac{6}{\frac{1\times 13+7}{13}}$$

Zero divided by any non-zero number gives zero.

$$1+0-\frac{6}{\frac{1\times 13+7}{13}}$$

Add 1 and 0 to get 1.

$$1-\frac{6}{\frac{1\times 13+7}{13}}$$

Divide 6 by \frac{1\times 13+7}{13} by multiplying 6 by the reciprocal of \frac{1\times 13+7}{13}.

$$1-\frac{6\times 13}{1\times 13+7}$$

Multiply 6 and 13 to get 78.

$$1-\frac{78}{1\times 13+7}$$

Multiply 1 and 13 to get 13.

$$1-\frac{78}{13+7}$$

Add 13 and 7 to get 20.

$$1-\frac{78}{20}$$

Reduce the fraction \frac{78}{20} to lowest terms by extracting and canceling out 2.

$$1-\frac{39}{10}$$

Convert 1 to fraction \frac{10}{10}.

$$\frac{10}{10}-\frac{39}{10}$$

Since \frac{10}{10} and \frac{39}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{10-39}{10}$$

Subtract 39 from 10 to get -29.

$$-\frac{29}{10}$$

Factor

$$-\frac{29}{10} = -2\frac{9}{10} = -2.9$$