Solve (1-(1/3+1/2))div2/9

$$( 1 - ( \frac { 1 } { 3 } + \frac { 1 } { 2 } ) ) \div \frac { 2 } { 9 }$$

Evaluate

$$\frac{3}{4}=0.75$$

Solution Steps

Least common multiple of 3 and 2 is 6. Convert \frac{1}{3} and \frac{1}{2} to fractions with denominator 6.

$$\frac{1-\left(\frac{2}{6}+\frac{3}{6}\right)}{\frac{2}{9}}$$

Since \frac{2}{6} and \frac{3}{6} have the same denominator, add them by adding their numerators.

$$\frac{1-\frac{2+3}{6}}{\frac{2}{9}}$$

Add 2 and 3 to get 5.

$$\frac{1-\frac{5}{6}}{\frac{2}{9}}$$

Convert 1 to fraction \frac{6}{6}.

$$\frac{\frac{6}{6}-\frac{5}{6}}{\frac{2}{9}}$$

Since \frac{6}{6} and \frac{5}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{6-5}{6}}{\frac{2}{9}}$$

Subtract 5 from 6 to get 1.

$$\frac{\frac{1}{6}}{\frac{2}{9}}$$

Divide \frac{1}{6} by \frac{2}{9} by multiplying \frac{1}{6} by the reciprocal of \frac{2}{9}.

$$\frac{1}{6}\times \frac{9}{2}$$

Multiply \frac{1}{6} times \frac{9}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 9}{6\times 2}$$

Do the multiplications in the fraction \frac{1\times 9}{6\times 2}.

$$\frac{9}{12}$$

Reduce the fraction \frac{9}{12} to lowest terms by extracting and canceling out 3.

$$\frac{3}{4}$$

Factor

$$\frac{3}{2 ^ {2}} = 0.75$$