Solve (1-sqrt[3]{-8})^-1-(10^-1+1/10)=

$$( 1 - \sqrt[ 3 ] { - 8 } ) ^ { - 1 } - ( 10 ^ { - 1 } + \frac { 1 } { 10 } ) =$$

Evaluate

$$\frac{2}{15}\approx 0.133333333$$

Solution Steps

Calculate \sqrt[3]{-8} and get -2.

$$\left(1-\left(-2\right)\right)^{-1}-\left(10^{-1}+\frac{1}{10}\right)$$

The opposite of -2 is 2.

$$\left(1+2\right)^{-1}-\left(10^{-1}+\frac{1}{10}\right)$$

Add 1 and 2 to get 3.

$$3^{-1}-\left(10^{-1}+\frac{1}{10}\right)$$

Calculate 3 to the power of -1 and get \frac{1}{3}.

$$\frac{1}{3}-\left(10^{-1}+\frac{1}{10}\right)$$

Calculate 10 to the power of -1 and get \frac{1}{10}.

$$\frac{1}{3}-\left(\frac{1}{10}+\frac{1}{10}\right)$$

Add \frac{1}{10} and \frac{1}{10} to get \frac{1}{5}.

$$\frac{1}{3}-\frac{1}{5}$$

Subtract \frac{1}{5} from \frac{1}{3} to get \frac{2}{15}.

$$\frac{2}{15}$$

Factor

$$\frac{2}{3 \cdot 5} = 0.13333333333333333$$