Solve (1-1/2)^2(-2)^3-3/2+-(-1/6)^2+frac{1/4-frac{1}{5}}{(1-frac{2}{5})^2}|-frac{frac{1}{3}-frac{2}{9}}{frac{1}{8}-frac{15}{8}}

$$( 1 - \frac { 1 } { 2 } ) ^ { 2 } ( - 2 ) ^ { 3 } - \frac { 3 } { 2 } + - ( - \frac { 1 } { 6 } ) ^ { 2 } + \frac { \frac { 1 } { 4 } - \frac { 1 } { 5 } } { ( 1 - \frac { 2 } { 5 } ) ^ { 2 } } | - \frac { \frac { 1 } { 3 } - \frac { 2 } { 9 } } { \frac { 1 } { 8 } - \frac { 15 } { 8 } }$$

Evaluate

$$-\frac{7981}{2268}\approx -3.518959436$$

Solution Steps

Subtract \frac{1}{2} from 1 to get \frac{1}{2}.

$$\left(\frac{1}{2}\right)^{2}\left(-2\right)^{3}-\frac{3}{2}-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{1}{4}\left(-2\right)^{3}-\frac{3}{2}-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Calculate -2 to the power of 3 and get -8.

$$\frac{1}{4}\left(-8\right)-\frac{3}{2}-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Multiply \frac{1}{4} and -8 to get -2.

$$-2-\frac{3}{2}-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Subtract \frac{3}{2} from -2 to get -\frac{7}{2}.

$$-\frac{7}{2}-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Calculate -\frac{1}{6} to the power of 2 and get \frac{1}{36}.

$$-\frac{7}{2}-\frac{1}{36}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Subtract \frac{1}{36} from -\frac{7}{2} to get -\frac{127}{36}.

$$-\frac{127}{36}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Subtract \frac{1}{5} from \frac{1}{4} to get \frac{1}{20}.

$$-\frac{127}{36}+\frac{\frac{1}{20}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Subtract \frac{2}{5} from 1 to get \frac{3}{5}.

$$-\frac{127}{36}+\frac{\frac{1}{20}}{\left(\frac{3}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Calculate \frac{3}{5} to the power of 2 and get \frac{9}{25}.

$$-\frac{127}{36}+\frac{\frac{1}{20}}{\frac{9}{25}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Divide \frac{1}{20} by \frac{9}{25} by multiplying \frac{1}{20} by the reciprocal of \frac{9}{25}.

$$-\frac{127}{36}+\frac{1}{20}\times \frac{25}{9}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Multiply \frac{1}{20} and \frac{25}{9} to get \frac{5}{36}.

$$-\frac{127}{36}+\frac{5}{36}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Subtract \frac{2}{9} from \frac{1}{3} to get \frac{1}{9}.

$$-\frac{127}{36}+\frac{5}{36}|-\frac{\frac{1}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Subtract \frac{15}{8} from \frac{1}{8} to get -\frac{7}{4}.

$$-\frac{127}{36}+\frac{5}{36}|-\frac{\frac{1}{9}}{-\frac{7}{4}}|$$

Divide \frac{1}{9} by -\frac{7}{4} by multiplying \frac{1}{9} by the reciprocal of -\frac{7}{4}.

$$-\frac{127}{36}+\frac{5}{36}|-\frac{1}{9}\left(-\frac{4}{7}\right)|$$

Multiply \frac{1}{9} and -\frac{4}{7} to get -\frac{4}{63}.

$$-\frac{127}{36}+\frac{5}{36}|-\left(-\frac{4}{63}\right)|$$

The opposite of -\frac{4}{63} is \frac{4}{63}.

$$-\frac{127}{36}+\frac{5}{36}|\frac{4}{63}|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of \frac{4}{63} is \frac{4}{63}.

$$-\frac{127}{36}+\frac{5}{36}\times \frac{4}{63}$$

Multiply \frac{5}{36} and \frac{4}{63} to get \frac{5}{567}.

$$-\frac{127}{36}+\frac{5}{567}$$

Add -\frac{127}{36} and \frac{5}{567} to get -\frac{7981}{2268}.

$$-\frac{7981}{2268}$$

Factor

$$-\frac{7981}{2268} = -3\frac{1177}{2268} = -3.5189594356261025$$