Solve (1-cos^2alpha)cosalpha=1/27(1+cosalpha)^3

Solve for α

\alpha =2\pi n_{2}+\left(-1\right)ArcCosI(\frac{25}{56}+\frac{3}{56}\times 57^{\frac{1}{2}})+2\pi \text{, }n_{2}\in \mathrm{Z}

\alpha =ArcCosI(\frac{25}{56}+\frac{3}{56}\times 57^{\frac{1}{2}})+2\pi n_{1}\text{, }n_{1}\in \mathrm{Z}

\alpha =\pi +2\pi n_{6}\text{, }n_{6}\in \mathrm{Z}

\alpha =2\pi n_{8}+\left(-1\right)ArcCosI(\frac{25}{56}+\left(-\frac{3}{56}\right)\times 57^{\frac{1}{2}})+2\pi \text{, }n_{8}\in \mathrm{Z}

\alpha =ArcCosI(\frac{25}{56}+\left(-\frac{3}{56}\right)\times 57^{\frac{1}{2}})+2\pi n_{7}\text{, }n_{7}\in \mathrm{Z}

Quiz

Trigonometry

5 problems similar to:

( 1 - \cos ^ { 2 } \alpha ) \cos \alpha = \frac { 1 } { 27 } ( 1 + \cos \alpha ) ^ { 3 }

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