Solve (1)5(n+2)^2=400

$$( 1 ) 5 ( n + 2 ) ^ { 2 } = 400$$

Solve for n

$$n=4\sqrt{5}-2\approx 6.94427191$$

$$n=-4\sqrt{5}-2\approx -10.94427191$$

Steps by Finding Square Root

Divide both sides by 5.

$$\frac{5\left(n+2\right)^{2}}{5}=\frac{400}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$\left(n+2\right)^{2}=\frac{400}{5}$$

Divide 400 by 5.

$$\left(n+2\right)^{2}=80$$

Take the square root of both sides of the equation.

$$n+2=4\sqrt{5} n+2=-4\sqrt{5}$$

Subtract 2 from both sides of the equation.

$$n+2-2=4\sqrt{5}-2 n+2-2=-4\sqrt{5}-2$$

Subtracting 2 from itself leaves 0.

$$n=4\sqrt{5}-2 n=-4\sqrt{5}-2$$