Solve (1)4a^2+3b^2+2ab-3a^2-4b^2

$$( 1 ) 4 a ^ { 2 } + 3 b ^ { 2 } + 2 a b - 3 a ^ { 2 } - 4 b ^ { 2 }$$

Evaluate

$$a^{2}+2ab-b^{2}$$

Solution Steps

Multiply 1 and 4 to get 4.

$$4a^{2}+3b^{2}+2ab-3a^{2}-4b^{2}$$

Combine 4a^{2} and -3a^{2} to get a^{2}.

$$a^{2}+3b^{2}+2ab-4b^{2}$$

Combine 3b^{2} and -4b^{2} to get -b^{2}.

$$a^{2}-b^{2}+2ab$$

Differentiate w.r.t. a

$$2\left(a+b\right)$$