Solve (1)4^-2*(1/2)^-3div(pi-2)^0

$$( 1 ) 4 ^ { - 2 } \times ( \frac { 1 } { 2 } ) ^ { - 3 } \div ( \pi - 2 ) ^ { 0 }$$

Evaluate

$$\frac{1}{2}=0.5$$

Solution Steps

Calculate 4 to the power of -2 and get \frac{1}{16}.

$$\frac{1\times \frac{1}{16}\times \left(\frac{1}{2}\right)^{-3}}{\left(\pi -2\right)^{0}}$$

Multiply 1 and \frac{1}{16} to get \frac{1}{16}.

$$\frac{\frac{1}{16}\times \left(\frac{1}{2}\right)^{-3}}{\left(\pi -2\right)^{0}}$$

Calculate \frac{1}{2} to the power of -3 and get 8.

$$\frac{\frac{1}{16}\times 8}{\left(\pi -2\right)^{0}}$$

Multiply \frac{1}{16} and 8 to get \frac{1}{2}.

$$\frac{\frac{1}{2}}{\left(\pi -2\right)^{0}}$$

Calculate \pi -2 to the power of 0 and get 1.

$$\frac{\frac{1}{2}}{1}$$

Anything divided by one gives itself.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$