Solve (1)3+2sin^222.5^circ

$$( 1 ) 3 + 2 \sin ^ { 2 } 22.5 ^ { \circ }$$

Evaluate

$$3.29289321881345251887535552412808$$

Solution Steps

Evaluate trigonometric functions in the problem

$${(1)} \cdot 3 + 2 \cdot 0.3826834323650898 ^ {2}$$

Multiply 1 and 3 to get 3.

$$3+2\times 0.3826834323650898^{2}$$

Calculate 0.3826834323650898 to the power of 2 and get 0.14644660940672625943767776206404.

$$3+2\times 0.14644660940672625943767776206404$$

Multiply 2 and 0.14644660940672625943767776206404 to get 0.29289321881345251887535552412808.

$$3+0.29289321881345251887535552412808$$

Add 3 and 0.29289321881345251887535552412808 to get 3.29289321881345251887535552412808.

$$3.29289321881345251887535552412808$$

Factor

$$\frac{3 \cdot 53 \cdot 149 \cdot 1231 \cdot 17191 \cdot 39822943 \cdot 2061634734437}{2 ^ {29} \cdot 5 ^ {32}} = 3\frac{3.66116523516816 \times 10^{30}}{1.2500000000000002 \times 10^{31}} = 3.292893218813453$$