Solve (1)sqrt[3]{18}-sqrt{32}+sqrt{2}

$$( 1 ) \sqrt[ 3 ] { 18 } - \sqrt { 32 } + \sqrt { 2 }$$

Evaluate

$$\sqrt[3]{18}-3\sqrt{2}\approx -1.621899293$$

Solution Steps

Factor 32=4^{2}\times 2. Rewrite the square root of the product \sqrt{4^{2}\times 2} as the product of square roots \sqrt{4^{2}}\sqrt{2}. Take the square root of 4^{2}.

$$1\sqrt[3]{18}-4\sqrt{2}+\sqrt{2}$$

Combine -4\sqrt{2} and \sqrt{2} to get -3\sqrt{2}.

$$1\sqrt[3]{18}-3\sqrt{2}$$

For any term t, t\times 1=t and 1t=t.

$$\sqrt[3]{18}-3\sqrt{2}$$