Solve (1*10^-4cm)*(0.4*15^4cm)

$$( 1 \times 10 ^ { - 4 } cm ) \times ( 0.4 \times 15 ^ { 4 } cm )$$

Evaluate

$$\frac{81\left(cm\right)^{2}}{40}$$

Solution Steps

Multiply c and c to get c^{2}.

$$1\times 10^{-4}c^{2}m\times 0.4\times 15^{4}m$$

Multiply m and m to get m^{2}.

$$1\times 10^{-4}c^{2}m^{2}\times 0.4\times 15^{4}$$

Calculate 10 to the power of -4 and get \frac{1}{10000}.

$$1\times \frac{1}{10000}c^{2}m^{2}\times 0.4\times 15^{4}$$

Multiply 1 and \frac{1}{10000} to get \frac{1}{10000}.

$$\frac{1}{10000}c^{2}m^{2}\times 0.4\times 15^{4}$$

Multiply \frac{1}{10000} and 0.4 to get \frac{1}{25000}.

$$\frac{1}{25000}c^{2}m^{2}\times 15^{4}$$

Calculate 15 to the power of 4 and get 50625.

$$\frac{1}{25000}c^{2}m^{2}\times 50625$$

Multiply \frac{1}{25000} and 50625 to get \frac{81}{40}.

$$\frac{81}{40}c^{2}m^{2}$$

Differentiate w.r.t. c

$$\frac{81cm^{2}}{20}$$