Solve (13/4div3)+1/4=c

$$( 1 \frac { 3 } { 4 } \div 3 ) + \frac { 1 } { 4 } = c$$

Solve for c

$$c=\frac{5}{6}\approx 0.833333333$$

Steps for Solving Linear Equation

Multiply 1 and 4 to get 4.

$$\frac{\frac{4+3}{4}}{3}+\frac{1}{4}=c$$

Add 4 and 3 to get 7.

$$\frac{\frac{7}{4}}{3}+\frac{1}{4}=c$$

Express \frac{\frac{7}{4}}{3} as a single fraction.

$$\frac{7}{4\times 3}+\frac{1}{4}=c$$

Multiply 4 and 3 to get 12.

$$\frac{7}{12}+\frac{1}{4}=c$$

Least common multiple of 12 and 4 is 12. Convert \frac{7}{12} and \frac{1}{4} to fractions with denominator 12.

$$\frac{7}{12}+\frac{3}{12}=c$$

Since \frac{7}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$\frac{7+3}{12}=c$$

Add 7 and 3 to get 10.

$$\frac{10}{12}=c$$

Reduce the fraction \frac{10}{12} to lowest terms by extracting and canceling out 2.

$$\frac{5}{6}=c$$

Swap sides so that all variable terms are on the left hand side.

$$c=\frac{5}{6}$$