Solve (11/9-11/12+1/24)*14.4

$$( 1 \frac { 1 } { 9 } - 1 \frac { 1 } { 12 } + \frac { 1 } { 24 } ) \cdot 14.4$$

Evaluate

$$1$$

Solution Steps

Multiply 1 and 9 to get 9.

$$\left(\frac{9+1}{9}-\frac{1\times 12+1}{12}+\frac{1}{24}\right)\times 14.4$$

Add 9 and 1 to get 10.

$$\left(\frac{10}{9}-\frac{1\times 12+1}{12}+\frac{1}{24}\right)\times 14.4$$

Multiply 1 and 12 to get 12.

$$\left(\frac{10}{9}-\frac{12+1}{12}+\frac{1}{24}\right)\times 14.4$$

Add 12 and 1 to get 13.

$$\left(\frac{10}{9}-\frac{13}{12}+\frac{1}{24}\right)\times 14.4$$

Least common multiple of 9 and 12 is 36. Convert \frac{10}{9} and \frac{13}{12} to fractions with denominator 36.

$$\left(\frac{40}{36}-\frac{39}{36}+\frac{1}{24}\right)\times 14.4$$

Since \frac{40}{36} and \frac{39}{36} have the same denominator, subtract them by subtracting their numerators.

$$\left(\frac{40-39}{36}+\frac{1}{24}\right)\times 14.4$$

Subtract 39 from 40 to get 1.

$$\left(\frac{1}{36}+\frac{1}{24}\right)\times 14.4$$

Least common multiple of 36 and 24 is 72. Convert \frac{1}{36} and \frac{1}{24} to fractions with denominator 72.

$$\left(\frac{2}{72}+\frac{3}{72}\right)\times 14.4$$

Since \frac{2}{72} and \frac{3}{72} have the same denominator, add them by adding their numerators.

$$\frac{2+3}{72}\times 14.4$$

Add 2 and 3 to get 5.

$$\frac{5}{72}\times 14.4$$

Convert decimal number 14.4 to fraction \frac{144}{10}. Reduce the fraction \frac{144}{10} to lowest terms by extracting and canceling out 2.

$$\frac{5}{72}\times \frac{72}{5}$$

Cancel out \frac{5}{72} and its reciprocal \frac{72}{5}.

$$1$$

Factor

$$1$$