Solve (11/3+23/5)div(4/3+13/5)

$$( 1 \frac { 1 } { 3 } + 2 \frac { 3 } { 5 } ) \div ( \frac { 4 } { 3 } + \frac { 13 } { 5 } )$$

Evaluate

$$1$$

Solution Steps

Multiply 1 and 3 to get 3.

$$\frac{\frac{3+1}{3}+\frac{2\times 5+3}{5}}{\frac{4}{3}+\frac{13}{5}}$$

Add 3 and 1 to get 4.

$$\frac{\frac{4}{3}+\frac{2\times 5+3}{5}}{\frac{4}{3}+\frac{13}{5}}$$

Multiply 2 and 5 to get 10.

$$\frac{\frac{4}{3}+\frac{10+3}{5}}{\frac{4}{3}+\frac{13}{5}}$$

Add 10 and 3 to get 13.

$$\frac{\frac{4}{3}+\frac{13}{5}}{\frac{4}{3}+\frac{13}{5}}$$

Least common multiple of 3 and 5 is 15. Convert \frac{4}{3} and \frac{13}{5} to fractions with denominator 15.

$$\frac{\frac{20}{15}+\frac{39}{15}}{\frac{4}{3}+\frac{13}{5}}$$

Since \frac{20}{15} and \frac{39}{15} have the same denominator, add them by adding their numerators.

$$\frac{\frac{20+39}{15}}{\frac{4}{3}+\frac{13}{5}}$$

Add 20 and 39 to get 59.

$$\frac{\frac{59}{15}}{\frac{4}{3}+\frac{13}{5}}$$

Least common multiple of 3 and 5 is 15. Convert \frac{4}{3} and \frac{13}{5} to fractions with denominator 15.

$$\frac{\frac{59}{15}}{\frac{20}{15}+\frac{39}{15}}$$

Since \frac{20}{15} and \frac{39}{15} have the same denominator, add them by adding their numerators.

$$\frac{\frac{59}{15}}{\frac{20+39}{15}}$$

Add 20 and 39 to get 59.

$$\frac{\frac{59}{15}}{\frac{59}{15}}$$

Divide \frac{59}{15} by \frac{59}{15} to get 1.

$$1$$

Factor

$$1$$