Solve (1^2-x)+(2^2-x)+(3^3-x)=50

$$( 1 ^ { 2 } - x ) + ( 2 ^ { 2 } - x ) + ( 3 ^ { 3 } - x ) = 50$$

Solve for x

$$x=-6$$

Steps for Solving Linear Equation

Calculate 1 to the power of 2 and get 1.

$$1-x+2^{2}-x+3^{3}-x=50$$

Calculate 2 to the power of 2 and get 4.

$$1-x+4-x+3^{3}-x=50$$

Add 1 and 4 to get 5.

$$5-x-x+3^{3}-x=50$$

Combine -x and -x to get -2x.

$$5-2x+3^{3}-x=50$$

Calculate 3 to the power of 3 and get 27.

$$5-2x+27-x=50$$

Add 5 and 27 to get 32.

$$32-2x-x=50$$

Combine -2x and -x to get -3x.

$$32-3x=50$$

Subtract 32 from both sides.

$$-3x=50-32$$

Subtract 32 from 50 to get 18.

$$-3x=18$$

Divide both sides by -3.

$$x=\frac{18}{-3}$$

Divide 18 by -3 to get -6.

$$x=-6$$