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1+3\sqrt{x}+3\left(\sqrt{x}\right)^{2}+\left(\sqrt{x}\right)^{3}+\left(1-\sqrt{x}\right)^{3}
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(1+\sqrt{x}\right)^{3}.
1+3\sqrt{x}+3x+\left(\sqrt{x}\right)^{3}+\left(1-\sqrt{x}\right)^{3}
Calculate \sqrt{x} to the power of 2 and get x.
1+3\sqrt{x}+3x+\left(\sqrt{x}\right)^{3}+1-3\sqrt{x}+3\left(\sqrt{x}\right)^{2}-\left(\sqrt{x}\right)^{3}
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(1-\sqrt{x}\right)^{3}.
1+3\sqrt{x}+3x+\left(\sqrt{x}\right)^{3}+1-3\sqrt{x}+3x-\left(\sqrt{x}\right)^{3}
Calculate \sqrt{x} to the power of 2 and get x.
2+3\sqrt{x}+3x+\left(\sqrt{x}\right)^{3}-3\sqrt{x}+3x-\left(\sqrt{x}\right)^{3}
Add 1 and 1 to get 2.
2+3x+\left(\sqrt{x}\right)^{3}+3x-\left(\sqrt{x}\right)^{3}
Combine 3\sqrt{x} and -3\sqrt{x} to get 0.
2+6x+\left(\sqrt{x}\right)^{3}-\left(\sqrt{x}\right)^{3}
Combine 3x and 3x to get 6x.
2+6x
Combine \left(\sqrt{x}\right)^{3} and -\left(\sqrt{x}\right)^{3} to get 0.
1+3\sqrt{x}+3\left(\sqrt{x}\right)^{2}+\left(\sqrt{x}\right)^{3}+\left(1-\sqrt{x}\right)^{3}
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(1+\sqrt{x}\right)^{3}.
1+3\sqrt{x}+3x+\left(\sqrt{x}\right)^{3}+\left(1-\sqrt{x}\right)^{3}
Calculate \sqrt{x} to the power of 2 and get x.
1+3\sqrt{x}+3x+\left(\sqrt{x}\right)^{3}+1-3\sqrt{x}+3\left(\sqrt{x}\right)^{2}-\left(\sqrt{x}\right)^{3}
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(1-\sqrt{x}\right)^{3}.
1+3\sqrt{x}+3x+\left(\sqrt{x}\right)^{3}+1-3\sqrt{x}+3x-\left(\sqrt{x}\right)^{3}
Calculate \sqrt{x} to the power of 2 and get x.
2+3\sqrt{x}+3x+\left(\sqrt{x}\right)^{3}-3\sqrt{x}+3x-\left(\sqrt{x}\right)^{3}
Add 1 and 1 to get 2.
2+3x+\left(\sqrt{x}\right)^{3}+3x-\left(\sqrt{x}\right)^{3}
Combine 3\sqrt{x} and -3\sqrt{x} to get 0.
2+6x+\left(\sqrt{x}\right)^{3}-\left(\sqrt{x}\right)^{3}
Combine 3x and 3x to get 6x.
2+6x
Combine \left(\sqrt{x}\right)^{3} and -\left(\sqrt{x}\right)^{3} to get 0.