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\left(1+\sqrt{2}+\sqrt{3}\right)\left(1+2\sqrt{2}\right)
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
1+2\sqrt{2}+\sqrt{2}+2\left(\sqrt{2}\right)^{2}+\sqrt{3}+2\sqrt{3}\sqrt{2}
Apply the distributive property by multiplying each term of 1+\sqrt{2}+\sqrt{3} by each term of 1+2\sqrt{2}.
1+3\sqrt{2}+2\left(\sqrt{2}\right)^{2}+\sqrt{3}+2\sqrt{3}\sqrt{2}
Combine 2\sqrt{2} and \sqrt{2} to get 3\sqrt{2}.
1+3\sqrt{2}+2\times 2+\sqrt{3}+2\sqrt{3}\sqrt{2}
The square of \sqrt{2} is 2.
1+3\sqrt{2}+4+\sqrt{3}+2\sqrt{3}\sqrt{2}
Multiply 2 and 2 to get 4.
5+3\sqrt{2}+\sqrt{3}+2\sqrt{3}\sqrt{2}
Add 1 and 4 to get 5.
5+3\sqrt{2}+\sqrt{3}+2\sqrt{6}
To multiply \sqrt{3} and \sqrt{2}, multiply the numbers under the square root.