Evaluate
16
Factor
2^{4}
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1+2\sqrt{15}+\left(\sqrt{15}\right)^{2}-\sqrt{60}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(1+\sqrt{15}\right)^{2}.
1+2\sqrt{15}+15-\sqrt{60}
The square of \sqrt{15} is 15.
16+2\sqrt{15}-\sqrt{60}
Add 1 and 15 to get 16.
16+2\sqrt{15}-2\sqrt{15}
Factor 60=2^{2}\times 15. Rewrite the square root of the product \sqrt{2^{2}\times 15} as the product of square roots \sqrt{2^{2}}\sqrt{15}. Take the square root of 2^{2}.
16
Combine 2\sqrt{15} and -2\sqrt{15} to get 0.
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