Solve (1+1/4)*(1+1/5)*(1+1/6)

$$( 1 + \frac { 1 } { 4 } ) \cdot ( 1 + \frac { 1 } { 5 } ) \cdot ( 1 + \frac { 1 } { 6 } )$$

Evaluate

$$\frac{7}{4}=1.75$$

Solution Steps

Convert 1 to fraction \frac{4}{4}.

$$\left(\frac{4}{4}+\frac{1}{4}\right)\left(1+\frac{1}{5}\right)\left(1+\frac{1}{6}\right)$$

Since \frac{4}{4} and \frac{1}{4} have the same denominator, add them by adding their numerators.

$$\frac{4+1}{4}\left(1+\frac{1}{5}\right)\left(1+\frac{1}{6}\right)$$

Add 4 and 1 to get 5.

$$\frac{5}{4}\left(1+\frac{1}{5}\right)\left(1+\frac{1}{6}\right)$$

Convert 1 to fraction \frac{5}{5}.

$$\frac{5}{4}\left(\frac{5}{5}+\frac{1}{5}\right)\left(1+\frac{1}{6}\right)$$

Since \frac{5}{5} and \frac{1}{5} have the same denominator, add them by adding their numerators.

$$\frac{5}{4}\times \frac{5+1}{5}\left(1+\frac{1}{6}\right)$$

Add 5 and 1 to get 6.

$$\frac{5}{4}\times \frac{6}{5}\left(1+\frac{1}{6}\right)$$

Multiply \frac{5}{4} times \frac{6}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5\times 6}{4\times 5}\left(1+\frac{1}{6}\right)$$

Cancel out 5 in both numerator and denominator.

$$\frac{6}{4}\left(1+\frac{1}{6}\right)$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}\left(1+\frac{1}{6}\right)$$

Convert 1 to fraction \frac{6}{6}.

$$\frac{3}{2}\left(\frac{6}{6}+\frac{1}{6}\right)$$

Since \frac{6}{6} and \frac{1}{6} have the same denominator, add them by adding their numerators.

$$\frac{3}{2}\times \frac{6+1}{6}$$

Add 6 and 1 to get 7.

$$\frac{3}{2}\times \frac{7}{6}$$

Multiply \frac{3}{2} times \frac{7}{6} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 7}{2\times 6}$$

Do the multiplications in the fraction \frac{3\times 7}{2\times 6}.

$$\frac{21}{12}$$

Reduce the fraction \frac{21}{12} to lowest terms by extracting and canceling out 3.

$$\frac{7}{4}$$

Factor

$$\frac{7}{2 ^ {2}} = 1\frac{3}{4} = 1.75$$