Solve (1+0.01/12)^4

$$( 1 + \frac { 0.01 } { 12 } ) ^ { 4 }$$

Evaluate

$$\frac{2080520644801}{2073600000000}\approx 1.003337502$$

Solution Steps

Expand \frac{0.01}{12} by multiplying both numerator and the denominator by 100.

$$\left(1+\frac{1}{1200}\right)^{4}$$

Add 1 and \frac{1}{1200} to get \frac{1201}{1200}.

$$\left(\frac{1201}{1200}\right)^{4}$$

Calculate \frac{1201}{1200} to the power of 4 and get \frac{2080520644801}{2073600000000}.

$$\frac{2080520644801}{2073600000000}$$

Factor

$$\frac{1201 ^ {4}}{2 ^ {16} \cdot 3 ^ {4} \cdot 5 ^ {8}} = 1\frac{6920644801}{2073600000000} = 1.003337502315297$$