Solve (1!+2!+3!+4!)*6

$$( 1 ! + 2 ! + 3 ! + 4 ! ) \times 6$$

Evaluate

$$198$$

Solution Steps

The factorial of 1 is 1.

$$\left(1+2!+3!+4!\right)\times 6$$

The factorial of 2 is 2.

$$\left(1+2+3!+4!\right)\times 6$$

Add 1 and 2 to get 3.

$$\left(3+3!+4!\right)\times 6$$

The factorial of 3 is 6.

$$\left(3+6+4!\right)\times 6$$

Add 3 and 6 to get 9.

$$\left(9+4!\right)\times 6$$

The factorial of 4 is 24.

$$\left(9+24\right)\times 6$$

Add 9 and 24 to get 33.

$$33\times 6$$

Multiply 33 and 6 to get 198.

$$198$$

Factor

$$2\times 3^{2}\times 11$$