Solve (02a^3+01b^2)04a^6+8

$$( 02 a ^ { 3 } + 01 b ^ { 2 } ) 04 a ^ { 6 } + 8$$

Evaluate

$$8$$

Solution Steps

Do the multiplications.

$$\left(0a^{3}+0b^{2}\right)\times 0\times 4a^{6}+8$$

Anything times zero gives zero.

$$\left(0+0b^{2}\right)\times 0\times 4a^{6}+8$$

Anything times zero gives zero.

$$\left(0+0\right)\times 0\times 4a^{6}+8$$

Add 0 and 0 to get 0.

$$0\times 0\times 4a^{6}+8$$

Multiply 0 and 0 to get 0.

$$0\times 4a^{6}+8$$

Multiply 0 and 4 to get 0.

$$0a^{6}+8$$

Anything times zero gives zero.

$$0+8$$

Add 0 and 8 to get 8.

$$8$$

Factor

$$2^{3}$$