Solve (0.98)^3+(0.02)^3+3*0.98*0.02-1}

$$( 0.98 ) ^ { 3 } + ( 0.02 ) ^ { 3 } + 3 \times 0.98 \times 0.02 - 1 \}$$

Evaluate

$$0$$

Solution Steps

Calculate 0.98 to the power of 3 and get 0.941192.

$$0.941192+0.02^{3}+3\times 0.98\times 0.02-1$$

Calculate 0.02 to the power of 3 and get 0.000008.

$$0.941192+0.000008+3\times 0.98\times 0.02-1$$

Add 0.941192 and 0.000008 to get 0.9412.

$$0.9412+3\times 0.98\times 0.02-1$$

Multiply 3 and 0.98 to get 2.94.

$$0.9412+2.94\times 0.02-1$$

Multiply 2.94 and 0.02 to get 0.0588.

$$0.9412+0.0588-1$$

Add 0.9412 and 0.0588 to get 1.

$$1-1$$

Subtract 1 from 1 to get 0.

$$0$$

Factor

$$0$$