Solve (0.85+j0.385)*(220/10.5)^2

$$( 0.85 + j 0.385 ) \times ( \frac { 220 } { 10.5 } ) ^ { 2 }$$

Evaluate

$$\frac{10648j_{0}}{63}+\frac{164560}{441}$$

Solution Steps

Expand \frac{220}{10.5} by multiplying both numerator and the denominator by 10.

$$\left(0.85+j_{0}\times 0.385\right)\times \left(\frac{2200}{105}\right)^{2}$$

Reduce the fraction \frac{2200}{105} to lowest terms by extracting and canceling out 5.

$$\left(0.85+j_{0}\times 0.385\right)\times \left(\frac{440}{21}\right)^{2}$$

Calculate \frac{440}{21} to the power of 2 and get \frac{193600}{441}.

$$\left(0.85+j_{0}\times 0.385\right)\times \frac{193600}{441}$$

Use the distributive property to multiply 0.85+j_{0}\times 0.385 by \frac{193600}{441}.

$$\frac{164560}{441}+\frac{193600}{441}j_{0}\times 0.385$$

Multiply \frac{193600}{441} and 0.385 to get \frac{10648}{63}.

$$\frac{164560}{441}+\frac{10648}{63}j_{0}$$

Expand

$$\frac{10648j_{0}}{63}+\frac{164560}{441}$$

Solution Steps

Expand \frac{220}{10.5} by multiplying both numerator and the denominator by 10.

$$\left(0.85+j_{0}\times 0.385\right)\times \left(\frac{2200}{105}\right)^{2}$$

Reduce the fraction \frac{2200}{105} to lowest terms by extracting and canceling out 5.

$$\left(0.85+j_{0}\times 0.385\right)\times \left(\frac{440}{21}\right)^{2}$$

Calculate \frac{440}{21} to the power of 2 and get \frac{193600}{441}.

$$\left(0.85+j_{0}\times 0.385\right)\times \frac{193600}{441}$$

Use the distributive property to multiply 0.85+j_{0}\times 0.385 by \frac{193600}{441}.

$$\frac{164560}{441}+\frac{193600}{441}j_{0}\times 0.385$$

Multiply \frac{193600}{441} and 0.385 to get \frac{10648}{63}.

$$\frac{164560}{441}+\frac{10648}{63}j_{0}$$