Solve (0.027)^frac{2{3}}+(125/27)^frac{1{3}}-(27/9)^0.5

$$( 0.027 ) ^ { \frac { 2 } { 3 } } + ( \frac { 125 } { 27 } ) ^ { \frac { 1 } { 3 } } - ( 2 \frac { 7 } { 9 } ) ^ { 0.5 }$$

Evaluate

$$0.09$$

Solution Steps

Calculate 0.027 to the power of \frac{2}{3} and get \frac{9}{100}.

$$\frac{9}{100}+\left(\frac{125}{27}\right)^{\frac{1}{3}}-\left(\frac{2\times 9+7}{9}\right)^{0.5}$$

Calculate \frac{125}{27} to the power of \frac{1}{3} and get \frac{5}{3}.

$$\frac{9}{100}+\frac{5}{3}-\left(\frac{2\times 9+7}{9}\right)^{0.5}$$

Add \frac{9}{100} and \frac{5}{3} to get \frac{527}{300}.

$$\frac{527}{300}-\left(\frac{2\times 9+7}{9}\right)^{0.5}$$

Multiply 2 and 9 to get 18.

$$\frac{527}{300}-\left(\frac{18+7}{9}\right)^{0.5}$$

Add 18 and 7 to get 25.

$$\frac{527}{300}-\left(\frac{25}{9}\right)^{0.5}$$

Calculate \frac{25}{9} to the power of 0.5 and get \frac{5}{3}.

$$\frac{527}{300}-\frac{5}{3}$$

Subtract \frac{5}{3} from \frac{527}{300} to get \frac{9}{100}.

$$\frac{9}{100}$$

Factor

$$\frac{3 ^ {2}}{2 ^ {2} \cdot 5 ^ {2}} = 0.09$$