Solve (0,4+3b)^2=0

$$( 0,4 + 3 b ) ^ { 2 } = 0$$

Solve for b

$$b=-\frac{2}{15}\approx -0,133333333$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$3b+0,4=0 3b+0,4=0$$

Subtract 0,4 from both sides of the equation.

$$3b+0,4-0,4=-0,4 3b+0,4-0,4=-0,4$$

Subtracting 0,4 from itself leaves 0.

$$3b=-0,4 3b=-0,4$$

Subtract 0,4 from 0.

$$3b=-0,4$$

Divide both sides by 3.

$$\frac{3b}{3}=-\frac{0,4}{3} \frac{3b}{3}=-\frac{0,4}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$b=-\frac{0,4}{3} b=-\frac{0,4}{3}$$

Divide -0,4 by 3.

$$b=-\frac{2}{15}$$