Solve (0.sqrt[3]{1}+3.5*1^5-sqrt[3]{27}):sqrt{144}

$$( 0 . \sqrt[ 3 ] { 1 } + 3.5 \cdot 1 ^ { 5 } - \sqrt[ 3 ] { 27 } ) : \sqrt { 144 }$$

Evaluate

$$\frac{1}{24}\approx 0.041666667$$

Solution Steps

Calculate \sqrt[3]{1} and get 1.

$$\frac{0\times 1+3.5\times 1^{5}-\sqrt[3]{27}}{\sqrt{144}}$$

Multiply 0 and 1 to get 0.

$$\frac{0+3.5\times 1^{5}-\sqrt[3]{27}}{\sqrt{144}}$$

Calculate 1 to the power of 5 and get 1.

$$\frac{0+3.5\times 1-\sqrt[3]{27}}{\sqrt{144}}$$

Multiply 3.5 and 1 to get 3.5.

$$\frac{0+3.5-\sqrt[3]{27}}{\sqrt{144}}$$

Add 0 and 3.5 to get 3.5.

$$\frac{3.5-\sqrt[3]{27}}{\sqrt{144}}$$

Calculate \sqrt[3]{27} and get 3.

$$\frac{3.5-3}{\sqrt{144}}$$

Subtract 3 from 3.5 to get 0.5.

$$\frac{0.5}{\sqrt{144}}$$

Calculate the square root of 144 and get 12.

$$\frac{0.5}{12}$$

Expand \frac{0.5}{12} by multiplying both numerator and the denominator by 10.

$$\frac{5}{120}$$

Reduce the fraction \frac{5}{120} to lowest terms by extracting and canceling out 5.

$$\frac{1}{24}$$

Factor

$$\frac{1}{3 \cdot 2 ^ {3}} = 0.041666666666666664$$