Solve (0sqrt[3]{1}+35*1^5-sqrt[3]{27}):sqrt{144}=

$$( 0 \sqrt[ 3 ] { 1 } + 35 \cdot 1 ^ { 5 } - \sqrt[ 3 ] { 27 } ) : \sqrt { 144 } =$$

Evaluate

$$\frac{8}{3}\approx 2.666666667$$

Solution Steps

Calculate \sqrt[3]{1} and get 1.

$$\frac{0\times 1+35\times 1^{5}-\sqrt[3]{27}}{\sqrt{144}}$$

Multiply 0 and 1 to get 0.

$$\frac{0+35\times 1^{5}-\sqrt[3]{27}}{\sqrt{144}}$$

Calculate 1 to the power of 5 and get 1.

$$\frac{0+35\times 1-\sqrt[3]{27}}{\sqrt{144}}$$

Multiply 35 and 1 to get 35.

$$\frac{0+35-\sqrt[3]{27}}{\sqrt{144}}$$

Add 0 and 35 to get 35.

$$\frac{35-\sqrt[3]{27}}{\sqrt{144}}$$

Calculate \sqrt[3]{27} and get 3.

$$\frac{35-3}{\sqrt{144}}$$

Subtract 3 from 35 to get 32.

$$\frac{32}{\sqrt{144}}$$

Calculate the square root of 144 and get 12.

$$\frac{32}{12}$$

Reduce the fraction \frac{32}{12} to lowest terms by extracting and canceling out 4.

$$\frac{8}{3}$$

Factor

$$\frac{2 ^ {3}}{3} = 2\frac{2}{3} = 2.6666666666666665$$