Solve (.1)^4+0.4(.1)^3-0.3(.1)^2-18

$$( .1 ) ^ { 4 } + 0.4 ( .1 ) ^ { 3 } - 0.3 ( .1 ) ^ { 2 } - 18$$

Evaluate

$$-18.0025$$

Solution Steps

Calculate 0.1 to the power of 4 and get 0.0001.

$$0.0001+0.4\times 0.1^{3}-0.3\times 0.1^{2}-18$$

Calculate 0.1 to the power of 3 and get 0.001.

$$0.0001+0.4\times 0.001-0.3\times 0.1^{2}-18$$

Multiply 0.4 and 0.001 to get 0.0004.

$$0.0001+0.0004-0.3\times 0.1^{2}-18$$

Add 0.0001 and 0.0004 to get 0.0005.

$$0.0005-0.3\times 0.1^{2}-18$$

Calculate 0.1 to the power of 2 and get 0.01.

$$0.0005-0.3\times 0.01-18$$

Multiply 0.3 and 0.01 to get 0.003.

$$0.0005-0.003-18$$

Subtract 0.003 from 0.0005 to get -0.0025.

$$-0.0025-18$$

Subtract 18 from -0.0025 to get -18.0025.

$$-18.0025$$

Factor

$$-18.0025$$