Solve (-x^2y)+x^2y^3)=

$$( - x ^ { 2 } y ) + x ^ { 2 } y ^ { 3 } ) =$$

Factor

$$y\left(y-1\right)\left(y+1\right)x^{2}$$

Solution Steps

Factor out x^{2}y.

$$x^{2}y\left(-1+y^{2}\right)$$

Consider -1+y^{2}. Rewrite -1+y^{2} as y^{2}-1^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(y-1\right)\left(y+1\right)$$

Rewrite the complete factored expression.

$$x^{2}y\left(y-1\right)\left(y+1\right)$$

Evaluate

$$yx^{2}\left(y^{2}-1\right)$$