Solve (-x+2-y)(-x-2-y)

$$( - x + 2 - y ) ( - x - 2 - y )$$

Evaluate

$$\left(x+y\right)^{2}-4$$

Solution Steps

Apply the distributive property by multiplying each term of -x+2-y by each term of -x-2-y.

$$\left(-x\right)^{2}-2\left(-x\right)-\left(-x\right)y+2\left(-x\right)-4-2y-y\left(-x\right)+2y+y^{2}$$

Calculate -x to the power of 2 and get x^{2}.

$$x^{2}-2\left(-x\right)-\left(-x\right)y+2\left(-x\right)-4-2y-y\left(-x\right)+2y+y^{2}$$

Multiply -2 and -1 to get 2.

$$x^{2}+2x-\left(-x\right)y+2\left(-x\right)-4-2y-y\left(-x\right)+2y+y^{2}$$

Multiply -1 and -1 to get 1.

$$x^{2}+2x+xy+2\left(-x\right)-4-2y-y\left(-x\right)+2y+y^{2}$$

Multiply -1 and -1 to get 1.

$$x^{2}+2x+xy+2\left(-x\right)-4-2y+yx+2y+y^{2}$$

Combine xy and yx to get 2xy.

$$x^{2}+2x+2xy+2\left(-x\right)-4-2y+2y+y^{2}$$

Combine -2y and 2y to get 0.

$$x^{2}+2x+2xy+2\left(-x\right)-4+y^{2}$$

Multiply 2 and -1 to get -2.

$$x^{2}+2x+2xy-2x-4+y^{2}$$

Combine 2x and -2x to get 0.

$$x^{2}+2xy-4+y^{2}$$

Expand

$$x^{2}+2xy+y^{2}-4$$

Solution Steps

Apply the distributive property by multiplying each term of -x+2-y by each term of -x-2-y.

$$\left(-x\right)^{2}-2\left(-x\right)-\left(-x\right)y+2\left(-x\right)-4-2y-y\left(-x\right)+2y+y^{2}$$

Calculate -x to the power of 2 and get x^{2}.

$$x^{2}-2\left(-x\right)-\left(-x\right)y+2\left(-x\right)-4-2y-y\left(-x\right)+2y+y^{2}$$

Multiply -2 and -1 to get 2.

$$x^{2}+2x-\left(-x\right)y+2\left(-x\right)-4-2y-y\left(-x\right)+2y+y^{2}$$

Multiply -1 and -1 to get 1.

$$x^{2}+2x+xy+2\left(-x\right)-4-2y-y\left(-x\right)+2y+y^{2}$$

Multiply -1 and -1 to get 1.

$$x^{2}+2x+xy+2\left(-x\right)-4-2y+yx+2y+y^{2}$$

Combine xy and yx to get 2xy.

$$x^{2}+2x+2xy+2\left(-x\right)-4-2y+2y+y^{2}$$

Combine -2y and 2y to get 0.

$$x^{2}+2x+2xy+2\left(-x\right)-4+y^{2}$$

Multiply 2 and -1 to get -2.

$$x^{2}+2x+2xy-2x-4+y^{2}$$

Combine 2x and -2x to get 0.

$$x^{2}+2xy-4+y^{2}$$