Solve for c
c=-\frac{2\sqrt[3]{x+1}}{x}
x\neq 0
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\left(-c\right)x=2\sqrt[3]{x+1}
Add -1 and 2 to get 1.
-cx=2\sqrt[3]{x+1}
Reorder the terms.
\left(-x\right)c=2\sqrt[3]{x+1}
The equation is in standard form.
\frac{\left(-x\right)c}{-x}=\frac{2\sqrt[3]{x+1}}{-x}
Divide both sides by -x.
c=\frac{2\sqrt[3]{x+1}}{-x}
Dividing by -x undoes the multiplication by -x.
c=-\frac{2\sqrt[3]{x+1}}{x}
Divide 2\sqrt[3]{x+1} by -x.
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