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\left(-a\right)^{2}-10\left(-a\right)+25
Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(-a-5\right)^{2}.
a^{2}-10\left(-a\right)+25
Calculate -a to the power of 2 and get a^{2}.
a^{2}+10a+25
Multiply -10 and -1 to get 10.
\left(-a\right)^{2}-10\left(-a\right)+25
Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(-a-5\right)^{2}.
a^{2}-10\left(-a\right)+25
Calculate -a to the power of 2 and get a^{2}.
a^{2}+10a+25
Multiply -10 and -1 to get 10.