Solve (-a^3b^6x^4)div(-2/3abx^3)

$$( - a ^ { 3 } b ^ { 6 } x ^ { 4 } ) \div ( - \frac { 2 } { 3 } a b x ^ { 3 } )$$

Evaluate

$$\frac{3xa^{2}b^{5}}{2}$$

Short Solution Steps

Cancel out bx^{3} in both numerator and denominator.

$$\frac{x\left(-a^{3}\right)b^{5}}{-\frac{2}{3}a}$$

Factor the expressions that are not already factored.

$$\frac{-xa^{3}b^{5}}{-\frac{2}{3}a}$$

Cancel out a in both numerator and denominator.

$$\frac{-xa^{2}b^{5}}{-\frac{2}{3}}$$

Divide -xa^{2}b^{5} by -\frac{2}{3} by multiplying -xa^{2}b^{5} by the reciprocal of -\frac{2}{3}.

$$\frac{-xa^{2}b^{5}\times 3}{-2}$$

Multiply -1 and 3 to get -3.

$$\frac{-3xa^{2}b^{5}}{-2}$$

Differentiate w.r.t. x

$$\frac{3a^{2}b^{5}}{2}$$