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-14x^{2}+7x-5+9
Combine -9x^{2} and -5x^{2} to get -14x^{2}.
-14x^{2}+7x+4
Add -5 and 9 to get 4.
factor(-14x^{2}+7x-5+9)
Combine -9x^{2} and -5x^{2} to get -14x^{2}.
factor(-14x^{2}+7x+4)
Add -5 and 9 to get 4.
-14x^{2}+7x+4=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-7±\sqrt{7^{2}-4\left(-14\right)\times 4}}{2\left(-14\right)}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-7±\sqrt{49-4\left(-14\right)\times 4}}{2\left(-14\right)}
Square 7.
x=\frac{-7±\sqrt{49+56\times 4}}{2\left(-14\right)}
Multiply -4 times -14.
x=\frac{-7±\sqrt{49+224}}{2\left(-14\right)}
Multiply 56 times 4.
x=\frac{-7±\sqrt{273}}{2\left(-14\right)}
Add 49 to 224.
x=\frac{-7±\sqrt{273}}{-28}
Multiply 2 times -14.
x=\frac{\sqrt{273}-7}{-28}
Now solve the equation x=\frac{-7±\sqrt{273}}{-28} when ± is plus. Add -7 to \sqrt{273}.
x=-\frac{\sqrt{273}}{28}+\frac{1}{4}
Divide -7+\sqrt{273} by -28.
x=\frac{-\sqrt{273}-7}{-28}
Now solve the equation x=\frac{-7±\sqrt{273}}{-28} when ± is minus. Subtract \sqrt{273} from -7.
x=\frac{\sqrt{273}}{28}+\frac{1}{4}
Divide -7-\sqrt{273} by -28.
-14x^{2}+7x+4=-14\left(x-\left(-\frac{\sqrt{273}}{28}+\frac{1}{4}\right)\right)\left(x-\left(\frac{\sqrt{273}}{28}+\frac{1}{4}\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{1}{4}-\frac{\sqrt{273}}{28} for x_{1} and \frac{1}{4}+\frac{\sqrt{273}}{28} for x_{2}.