Solve (-9)^2+(2^3)^2+(-9+8)^2

$$( - 9 ) ^ { 2 } + ( 2 ^ { 3 } ) ^ { 2 } + ( - 9 + 8 ) ^ { 2 }$$

Evaluate

$$146$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$\left(-9\right)^{2}+2^{6}+\left(-9+8\right)^{2}$$

Calculate -9 to the power of 2 and get 81.

$$81+2^{6}+\left(-9+8\right)^{2}$$

Calculate 2 to the power of 6 and get 64.

$$81+64+\left(-9+8\right)^{2}$$

Add 81 and 64 to get 145.

$$145+\left(-9+8\right)^{2}$$

Add -9 and 8 to get -1.

$$145+\left(-1\right)^{2}$$

Calculate -1 to the power of 2 and get 1.

$$145+1$$

Add 145 and 1 to get 146.

$$146$$

Factor

$$2\times 73$$