Solve (-8)+(-2)-6div(2-5)+(10div(-2)-3div(1-2))

$$( - 8 ) + ( - 2 ) - 6 \div ( 2 - 5 ) + ( 10 \div ( - 2 ) - 3 \div ( 1 - 2 ) )$$

Evaluate

$$-10$$

Solution Steps

Subtract 2 from -8 to get -10.

$$-10-\frac{6}{2-5}+\frac{10}{-2}-\frac{3}{1-2}$$

Subtract 5 from 2 to get -3.

$$-10-\frac{6}{-3}+\frac{10}{-2}-\frac{3}{1-2}$$

Divide 6 by -3 to get -2.

$$-10-\left(-2\right)+\frac{10}{-2}-\frac{3}{1-2}$$

The opposite of -2 is 2.

$$-10+2+\frac{10}{-2}-\frac{3}{1-2}$$

Add -10 and 2 to get -8.

$$-8+\frac{10}{-2}-\frac{3}{1-2}$$

Divide 10 by -2 to get -5.

$$-8-5-\frac{3}{1-2}$$

Subtract 5 from -8 to get -13.

$$-13-\frac{3}{1-2}$$

Subtract 2 from 1 to get -1.

$$-13-\frac{3}{-1}$$

Fraction \frac{3}{-1} can be rewritten as -3 by extracting the negative sign.

$$-13-\left(-3\right)$$

The opposite of -3 is 3.

$$-13+3$$

Add -13 and 3 to get -10.

$$-10$$

Factor

$$-10$$