Solve (-7xb^2)*(-5x^2b^4)

$$( - 7 x b ^ { 2 } ) \cdot ( - 5 x ^ { 2 } b ^ { 4 } )$$

Evaluate

$$35x^{3}b^{6}$$

Steps Using Commutative Property of Multiplication

Use the rules of exponents to simplify the expression.

$$\left(-7\right)^{1}x^{1}b^{2}\left(-5\right)^{1}x^{2}b^{4}$$

Use the Commutative Property of Multiplication.

$$\left(-7\right)^{1}\left(-5\right)^{1}x^{1}x^{2}b^{2}b^{4}$$

To multiply powers of the same base, add their exponents.

$$\left(-7\right)^{1}\left(-5\right)^{1}x^{1+2}b^{2+4}$$

Add the exponents 1 and 2.

$$\left(-7\right)^{1}\left(-5\right)^{1}x^{3}b^{2+4}$$

Add the exponents 2 and 4.

$$\left(-7\right)^{1}\left(-5\right)^{1}x^{3}b^{6}$$

Multiply -7 times -5.

$$35x^{3}b^{6}$$

Differentiate w.r.t. x

$$105x^{2}b^{6}$$