Solve (-7)^5:(-7)^4-(-5)^3-9^2:(-9)

$$( - 7 ) ^ { 5 } : ( - 7 ) ^ { 4 } - ( - 5 ) ^ { 3 } - 9 ^ { 2 } : ( - 9 )$$

Evaluate

$$127$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 4 from 5 to get 1.

$$\left(-7\right)^{1}-\left(-5\right)^{3}-\frac{9^{2}}{-9}$$

Calculate -7 to the power of 1 and get -7.

$$-7-\left(-5\right)^{3}-\frac{9^{2}}{-9}$$

Calculate -5 to the power of 3 and get -125.

$$-7-\left(-125\right)-\frac{9^{2}}{-9}$$

The opposite of -125 is 125.

$$-7+125-\frac{9^{2}}{-9}$$

Add -7 and 125 to get 118.

$$118-\frac{9^{2}}{-9}$$

Calculate 9 to the power of 2 and get 81.

$$118-\frac{81}{-9}$$

Divide 81 by -9 to get -9.

$$118-\left(-9\right)$$

The opposite of -9 is 9.

$$118+9$$

Add 118 and 9 to get 127.

$$127$$

Factor

$$127$$