Solve (-7)^2*(-7)^5*(-7)^-9?

$$( - 7 ) ^ { 2 } \cdot ( - 7 ) ^ { 5 } \cdot ( - 7 ) ^ { - 9 } ?$$

Evaluate

$$\frac{1}{49}\approx 0.020408163$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 5 to get 7.

$$\left(-7\right)^{7}\left(-7\right)^{-9}$$

To multiply powers of the same base, add their exponents. Add 7 and -9 to get -2.

$$\left(-7\right)^{-2}$$

Calculate -7 to the power of -2 and get \frac{1}{49}.

$$\frac{1}{49}$$

Factor

$$\frac{1}{7 ^ {2}} = 0.02040816326530612$$