Solve (-7+2)-(3(-7)-1)^2=(-2^2+4)

$$( - 7 + 2 ) - ( 3 ( - 7 ) - 1 ) ^ { 2 } = ( - 2 ^ { 2 } + 4 )$$

Verify

Solution Steps

Add -7 and 2 to get -5.

$$-5-\left(3\left(-7\right)-1\right)^{2}=-2^{2}+4$$

Multiply 3 and -7 to get -21.

$$-5-\left(-21-1\right)^{2}=-2^{2}+4$$

Subtract 1 from -21 to get -22.

$$-5-\left(-22\right)^{2}=-2^{2}+4$$

Calculate -22 to the power of 2 and get 484.

$$-5-484=-2^{2}+4$$

Subtract 484 from -5 to get -489.

$$-489=-2^{2}+4$$

Calculate 2 to the power of 2 and get 4.

$$-489=-4+4$$

Add -4 and 4 to get 0.

$$-489=0$$

Compare -489 and 0.

$$\text{false}$$