Solve (-6)*8-(-2)^3-(-4)^2*5

$$( - 6 ) \times 8 - ( - 2 ) ^ { 3 } - ( - 4 ) ^ { 2 } \times 5$$

Evaluate

$$-120$$

Solution Steps

Multiply -6 and 8 to get -48.

$$-48-\left(-2\right)^{3}-\left(-4\right)^{2}\times 5$$

Calculate -2 to the power of 3 and get -8.

$$-48-\left(-8\right)-\left(-4\right)^{2}\times 5$$

The opposite of -8 is 8.

$$-48+8-\left(-4\right)^{2}\times 5$$

Add -48 and 8 to get -40.

$$-40-\left(-4\right)^{2}\times 5$$

Calculate -4 to the power of 2 and get 16.

$$-40-16\times 5$$

Multiply 16 and 5 to get 80.

$$-40-80$$

Subtract 80 from -40 to get -120.

$$-120$$

Factor

$$-120$$