Solve (-62/11)div(-18/9)

$$( - 6 \frac { 2 } { 11 } ) \div ( - 1 \frac { 8 } { 9 } )$$

Evaluate

$$\frac{36}{11}\approx 3.272727273$$

Solution Steps

Multiply 6 and 11 to get 66.

$$\frac{-\frac{66+2}{11}}{-\frac{1\times 9+8}{9}}$$

Add 66 and 2 to get 68.

$$\frac{-\frac{68}{11}}{-\frac{1\times 9+8}{9}}$$

Multiply 1 and 9 to get 9.

$$\frac{-\frac{68}{11}}{-\frac{9+8}{9}}$$

Add 9 and 8 to get 17.

$$\frac{-\frac{68}{11}}{-\frac{17}{9}}$$

Divide -\frac{68}{11} by -\frac{17}{9} by multiplying -\frac{68}{11} by the reciprocal of -\frac{17}{9}.

$$-\frac{68}{11}\left(-\frac{9}{17}\right)$$

Multiply -\frac{68}{11} times -\frac{9}{17} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-68\left(-9\right)}{11\times 17}$$

Do the multiplications in the fraction \frac{-68\left(-9\right)}{11\times 17}.

$$\frac{612}{187}$$

Reduce the fraction \frac{612}{187} to lowest terms by extracting and canceling out 17.

$$\frac{36}{11}$$

Factor

$$\frac{2 ^ {2} \cdot 3 ^ {2}}{11} = 3\frac{3}{11} = 3.272727272727273$$