Solve (-6^2)*(-4/9)div(-2)^3

$$( - 6 ^ { 2 } ) \times ( - \frac { 4 } { 9 } ) \div ( - 2 ) ^ { 3 }$$

Evaluate

$$-2$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$\frac{-36\left(-\frac{4}{9}\right)}{\left(-2\right)^{3}}$$

Express -36\left(-\frac{4}{9}\right) as a single fraction.

$$\frac{\frac{-36\left(-4\right)}{9}}{\left(-2\right)^{3}}$$

Multiply -36 and -4 to get 144.

$$\frac{\frac{144}{9}}{\left(-2\right)^{3}}$$

Divide 144 by 9 to get 16.

$$\frac{16}{\left(-2\right)^{3}}$$

Calculate -2 to the power of 3 and get -8.

$$\frac{16}{-8}$$

Divide 16 by -8 to get -2.

$$-2$$

Factor

$$-2$$