Evaluate
\text{Indeterminate}
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25+10\sqrt{-6}+\left(\sqrt{-6}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(-5-\sqrt{-6}\right)^{2}.
25+10\sqrt{-6}-6
Calculate \sqrt{-6} to the power of 2 and get -6.
19+10\sqrt{-6}
Subtract 6 from 25 to get 19.
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