Solve (-5)^2*[(-4)^3+(-1)^12]+(-42)^0

$$( - 5 ) ^ { 2 } \cdot [ ( - 4 ) ^ { 3 } + ( - 1 ) ^ { 12 } ] + ( - 42 ) ^ { 0 }$$

Evaluate

$$-1574$$

Solution Steps

Calculate -5 to the power of 2 and get 25.

$$25\left(\left(-4\right)^{3}+\left(-1\right)^{12}\right)+\left(-42\right)^{0}$$

Calculate -4 to the power of 3 and get -64.

$$25\left(-64+\left(-1\right)^{12}\right)+\left(-42\right)^{0}$$

Calculate -1 to the power of 12 and get 1.

$$25\left(-64+1\right)+\left(-42\right)^{0}$$

Add -64 and 1 to get -63.

$$25\left(-63\right)+\left(-42\right)^{0}$$

Multiply 25 and -63 to get -1575.

$$-1575+\left(-42\right)^{0}$$

Calculate -42 to the power of 0 and get 1.

$$-1575+1$$

Add -1575 and 1 to get -1574.

$$-1574$$

Factor

$$-1574$$