Solve (-5)^2:(-5)+3^3:(-9)-|-6|

$$( - 5 ) ^ { 2 } : ( - 5 ) + 3 ^ { 3 } : ( - 9 ) - | - 6 |$$

Evaluate

$$-14$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 2 to get 1.

$$\left(-5\right)^{1}+\frac{3^{3}}{-9}-|-6|$$

Calculate -5 to the power of 1 and get -5.

$$-5+\frac{3^{3}}{-9}-|-6|$$

Calculate 3 to the power of 3 and get 27.

$$-5+\frac{27}{-9}-|-6|$$

Divide 27 by -9 to get -3.

$$-5-3-|-6|$$

Subtract 3 from -5 to get -8.

$$-8-|-6|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -6 is 6.

$$-8-6$$

Subtract 6 from -8 to get -14.

$$-14$$

Factor

$$-14$$