Solve (-5+b^3)^2

$$( - 5 + b ^ { 3 } ) ^ { 2 }$$

Evaluate

$$\left(b^{3}-5\right)^{2}$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(-5+b^{3}\right)^{2}.

$$25-10b^{3}+\left(b^{3}\right)^{2}$$

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$25-10b^{3}+b^{6}$$

Expand

$$b^{6}-10b^{3}+25$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(-5+b^{3}\right)^{2}.

$$25-10b^{3}+\left(b^{3}\right)^{2}$$

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$25-10b^{3}+b^{6}$$