Solve (-5+6div3)+4-7[2-5|-6|]

$$( - 5 + 6 \div 3 ) + 4 - 7 [ 2 - 5 | - 6 | ]$$

Evaluate

$$197$$

Solution Steps

Divide 6 by 3 to get 2.

$$-5+2+4-7\left(2-5|-6|\right)$$

Add -5 and 2 to get -3.

$$-3+4-7\left(2-5|-6|\right)$$

Add -3 and 4 to get 1.

$$1-7\left(2-5|-6|\right)$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -6 is 6.

$$1-7\left(2-5\times 6\right)$$

Multiply 5 and 6 to get 30.

$$1-7\left(2-30\right)$$

Subtract 30 from 2 to get -28.

$$1-7\left(-28\right)$$

Multiply 7 and -28 to get -196.

$$1-\left(-196\right)$$

The opposite of -196 is 196.

$$1+196$$

Add 1 and 196 to get 197.

$$197$$

Factor

$$197$$