Solve (-48,3):(63/10-(-3/5))

$$( - 48,3 ) : ( 6 \frac { 3 } { 10 } - ( - \frac { 3 } { 5 } ) )$$

Evaluate

$$-7$$

Solution Steps

Multiply 6 and 10 to get 60.

$$\frac{-48,3}{\frac{60+3}{10}-\left(-\frac{3}{5}\right)}$$

Add 60 and 3 to get 63.

$$\frac{-48,3}{\frac{63}{10}-\left(-\frac{3}{5}\right)}$$

The opposite of -\frac{3}{5} is \frac{3}{5}.

$$\frac{-48,3}{\frac{63}{10}+\frac{3}{5}}$$

Least common multiple of 10 and 5 is 10. Convert \frac{63}{10} and \frac{3}{5} to fractions with denominator 10.

$$\frac{-48,3}{\frac{63}{10}+\frac{6}{10}}$$

Since \frac{63}{10} and \frac{6}{10} have the same denominator, add them by adding their numerators.

$$\frac{-48,3}{\frac{63+6}{10}}$$

Add 63 and 6 to get 69.

$$\frac{-48,3}{\frac{69}{10}}$$

Divide -48,3 by \frac{69}{10} by multiplying -48,3 by the reciprocal of \frac{69}{10}.

$$-48,3\times \frac{10}{69}$$

Convert decimal number -48,3 to fraction -\frac{483}{10}.

$$-\frac{483}{10}\times \frac{10}{69}$$

Multiply -\frac{483}{10} times \frac{10}{69} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-483\times 10}{10\times 69}$$

Cancel out 10 in both numerator and denominator.

$$\frac{-483}{69}$$

Divide -483 by 69 to get -7.

$$-7$$

Factor

$$-7$$